Question

A single loop of current is immersed in an externally applied uniform magnetic field of 3 Tesla oriented in the positive y direction: begin mathsize 12px style B with rightwards arrow on top equals 3 space j with logical and on top end style T. The loop carries a 1/2 amp current, I = 0.5 A. If the lengths of the sides of the loop are 4 m and 2 m, what is the magnitude of the magnetic moment, mu, of the loop?

Answer 1

mu=12Tm^2

Step-by-step explanation:

the magnetic moment mu of a single loop is given by:

`\mu = I A B`

where I is the current, B is the magnetic field and A is the area of the loop. By replacing we obtain:

`\mu=(0.5A)(4m*2m)(3T)=12Tm^2`

hope this helps!!