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When a certain paramagnetic material is placed in an external magnetic field of 1.50T , the field inside the material is measured to be 1.5023T .

Part A


The relative permeability of this material is


1.0015.


0.0015.


1.


10.015



Part B


The magnetic permeability of this material is


0T.m/A.


1.259.10?7T.m/A.


1.259.10?6T.m/A.


1.259.10?5T.m/A.

1 Answer

5 votes

Answer:

The relative permeability of material is 1.0015 and magnetic permeability of material is
1.259 * 10^(-6)

Step-by-step explanation:

Part A:

Given:

Magnetic field in material
B = 1.5023 T

Magnetic field in air
B_(o) = 1.50 T

The relative permeability of material is given by,


\mu _(r) = (B)/(B_(o) )


\mu _(r) = (1.5023)/(1.50)


\mu _(r) = 1.0015

Part B:

The magnetic permeability of material is given by,


\mu _(r) = (\mu)/(\mu _(o) )

Where
\mu _(o) = 4 \pi * 10^(-7)


\mu = \mu _(r) \mu _(0)


\mu = 1.0015 * 4 \pi * 10^(-7)


\mu = 1.259 * 10^(-6)

Therefore, the relative permeability of material is 1.0015 and magnetic permeability of material is
1.259 * 10^(-6)

User Shabbir Bata
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