Question

When a certain paramagnetic material is placed in an external magnetic field of 1.50T , the field inside the material is measured to be 1.5023T .

Part A


The relative permeability of this material is


1.0015.


0.0015.


1.


10.015



Part B


The magnetic permeability of this material is


0T.m/A.


1.259.10?7T.m/A.


1.259.10?6T.m/A.


1.259.10?5T.m/A.

Answer 1

The relative permeability of material is 1.0015 and magnetic permeability of material is
`1.259 * 10^(-6)`

Step-by-step explanation:

Part A:

Given:

Magnetic field in material
`B = 1.5023` T

Magnetic field in air
`B_(o) = 1.50` T

The relative permeability of material is given by,

`\mu _(r) = (B)/(B_(o) )`

`\mu _(r) = (1.5023)/(1.50)`

`\mu _(r) = 1.0015`

Part B:

The magnetic permeability of material is given by,

`\mu _(r) = (\mu)/(\mu _(o) )`

Where
`\mu _(o) = 4 \pi * 10^(-7)`

`\mu = \mu _(r) \mu _(0)`

`\mu = 1.0015 * 4 \pi * 10^(-7)`

`\mu = 1.259 * 10^(-6)`

Therefore, the relative permeability of material is 1.0015 and magnetic permeability of material is
`1.259 * 10^(-6)`