Answer:
It will increase by 24 starfish
Explanation:
The population is modeled by the following differential equation:
![(dN)/(dt) = rN](https://img.qammunity.org/2021/formulas/mathematics/college/64zk4br0j3t4xctlzpcgpaiup90y08kuh5.png)
Which has the following solution:
![N(t) = N(0)e^(rt)](https://img.qammunity.org/2021/formulas/mathematics/college/3zvzr66xcmljz62qhguqmu7yn08241j19w.png)
In which N(0) is the initial population and r is the growth rate.
A population of 2000 starfish has a yearly per capita population growth rate of 0.012.
This means that
![N(0) = 2000, r = 0.012](https://img.qammunity.org/2021/formulas/mathematics/college/re1dla89lu8pawg3isq5aqo60n0cjc6d38.png)
By next year, how do you expect population size to have changed?
This is N(1).
![N(t) = N(0)e^(rt)](https://img.qammunity.org/2021/formulas/mathematics/college/3zvzr66xcmljz62qhguqmu7yn08241j19w.png)
![N(1) = 2000*e^(0.012)](https://img.qammunity.org/2021/formulas/mathematics/college/xaj73oemxdxxa3ocykigdq2tgcsyqbzt4y.png)
![N(1) = 2024](https://img.qammunity.org/2021/formulas/mathematics/college/scgm40lw9wrrlelsv8xitj1visjgdhm639.png)
2024 - 2000 = 24
So the correct answer is:
It will increase by 24 starfish