Answer:
0.56
Step-by-step explanation:
Step 1:
Data obtained from the question.
Mass of HCl = 10g
Volume = 1000mL = 1L
Step 2:
Determination of the mole of HCl. This can be obtained as follow:
Molar Mass of HCl = 1 + 35.5 = 36.5g/mol
Mass of HCl = 10g
Mole of HCl =?
Number of mole = Mass/Molar Mass
Mole of HCl = 10/36.5
Mole of HCl = 0.274 mole
Step 3:
Determination of the molarity of HCl. This is illustrated below:
Mole of solute (HCl) = 0.274 mole
Volume = 1L
Molarity =?
Molarity is simply the mole of solute per unit litre of the solution. It is represented mathematically as:
Molarity = mole of solute/Volume of solution
Molarity of HCl = 0.274 mole/1L
Molarity of HCl = 0.274 mol/L
Step 4:
Determination of the hydrogen ion concentration [H+] in 0.274 mol/L HCl.
We'll begin by writing a balanced dissociation equation for HCl. This is shown below:
HCl —> H+ + Cl-
From the above equation, 1 mole of HCl produced 1 mole H+
Therefore, 0.274 mol/L of HCl will also produce 0.274 mol/L of H+
Step 5:
Determination of the pH of the solution.
The pH of a solution is simply the negative logarithm of the hydrogen ion concentration [H+] in the solution. It is represented mathematically as:
pH = - log [H+]
[H+] = 0.274 mol/L
pH = - log [H+]
pH = - log 0.274
pH = 0.56
Therefore, the pH of the solution made by dissolving 10 grams of hydrogen chloride in 1000 mL of water is 0.56