Question

In an AC circuit with a single inductor L=1mH, what is the frequency if Irms=1.6A when Vrms=10V?

Answer 1

994.718Hz

Step-by-step explanation:

[V(rms) / I(rms)] = 2ΠfL

Vrms = 10V

Irms = 1.6A

L = 1mH = 1*10⁻³H

f = ?

[V(rms) / I(rms)] = 2ΠfL

10 / 1.6 = 2π*1*10⁻³f

6.25 = 6.28*10⁻³f

f = 994.718Hz

The frequency across the inductor is 994.718Hz