Question

In ΔNOP, the measure of ∠P=90°, ON = 5, PO = 3, and NP = 4. What is the value of the sine of ∠N to the nearest hundredth?

Answer 1

Answer : The value of
`\sin \angle N` is, 0.60

Step-by-step explanation :

Given:

In right angle triangle NPO,

∠P = 90°

ON = 5

PO = 3

NP = 4

According to trigonometric function,

`\sin \theta=(Perpendicular)/(Hypotenuse)`

`\sin \angle N=(PO)/(ON)`

`\sin \angle N=(3)/(5)=0.60`

Thus, the value of
`\sin \angle N` is, 0.60