Question

A current I = 17 A is directed along the positive x-axis and perpendicular to a magnetic field. A magnetic force per unit length of 0.19 N/m acts on the conductor in the negative y-direction. Calculate the magnitude and direction of the magnetic field in the region through which the current passes. magnitude T direction.

Answer 1

The magnitude of magnetic field is 0.011 T in +z direction.

Step-by-step explanation:

Given that,

Current, I = 17 A

The magnetic force per unit length,
`(F)/(l)=0.19\ N/m`

We need to find the magnitude and direction of the magnetic field in the region through which the current passes. The magnetic force acting on the conductor is given by :

`F=ilB`

B is magnetic field

`B=(F)/(il)\\\\B=(0.19)/(17)\\\\B=0.011\ T`

For direction,

`(F)/(l)(-j)=i(+i) B`

The magnetic field is in +z direction. Hence, this is the required solution.