Answer:
The answer is: 4.53 m, 4.03 m, 2.13 m, 0.93 m,..., are the values of x constructive interference occur at point P
Step-by-step explanation:
The wavelength is:
![\lambda =(v)/(f)](https://img.qammunity.org/2021/formulas/physics/college/lxva21w3n473rwczsx3ml1mn1404jpmooy.png)
Where
v = 3x10⁸m/s
f = 125 MHz = 125x10⁶Hz
Replacing:
![\lambda =(3x10^(8) )/(125x10^(6) ) =2.4m](https://img.qammunity.org/2021/formulas/physics/college/i4hn0uirc0xklom51alt5l2evroallce39.png)
The expression of path difference is equal:
9.05 - x - x = 9.05 -2x (exp. 1)
nλ (exp. 2)
Matching both expressions:
9.05 - 2x = nλ
9.05 - 2x = 2.4λ
Integers for n between 0 and 9.05
For n = 0
![9.05-2x=0*2.4\\9.05-2x=0\\2x=9.05\\x=(9.05)/(2) =4.53m](https://img.qammunity.org/2021/formulas/physics/college/315iyqd3f7gv8okto4qacs26x3cc0oiaph.png)
For n = 1
![9.05-2x=1*2.4\\9.05-2x=1\\2x=9.05-1\\x=(8.05)/(2) =4.03m](https://img.qammunity.org/2021/formulas/physics/college/f94wi493cpjumoevlq5miisp6r8a294azh.png)
For n = 2
![9.05-2x=2*2.4\\9.05-2x=4.8\\2x=9.05-4.8\\x=(4.25)/(2) =2.13m](https://img.qammunity.org/2021/formulas/physics/college/oolvrrw3rr2t0zn6btp367m08nsfxdgq0x.png)
For n = 3
![9.05-2x=3*2.4\\9.05-2x=7.2\\2x=9.05-7.2\\x=(1.85)/(2) =0.93m](https://img.qammunity.org/2021/formulas/physics/college/1sx47g0pujo1rxiskydppvh03mxg9n25t7.png)