Answer:
0.06
Explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean
and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the standard deviation is
.
In this problem, we have that:
![p = 0.2, n = 50](https://img.qammunity.org/2021/formulas/mathematics/college/t3faiwhcgxops2qy3262cw9pu7xdpywj6q.png)
So
![s = \sqrt{(p(1-p))/(n)}](https://img.qammunity.org/2021/formulas/mathematics/college/4g01jif87kw0yiycg79zy61z1uo268l9th.png)
![s = \sqrt{(0.2*0.8)/(50)}](https://img.qammunity.org/2021/formulas/mathematics/college/ipc1iiqhrmk00treujrl8bd5vfzn40oxfo.png)
![s = 0.06](https://img.qammunity.org/2021/formulas/mathematics/college/1u2a2pauhxphxr9e8c9ijfv4ajgcufhcoz.png)