Question

A marble is selected at random from a jar containing 3 red​ marbles, 4 yellow​ marbles, and 6 green marbles. What is the probability that ​a) the marble is​ red? ​b) the marble is not​ yellow? ​c) the marble is either red or ​green? ​d) the marble is neither red nor ​green?A marble is selected at random from a jar containing 33 red​ marbles, 44 yellow​ marbles, and 66 green marbles. What is the probability that ​a) the marble is​ red? ​b) the marble is not​ yellow? ​c) the marble is either red or ​green? ​d) the marble is neither red nor ​green?

Answer 1

Answer: a)
`(3)/(13),\ b)(9)/(13)\ c)(9)/(13),\ d)(4)/(13)`

Explanation:

Since we have given that

Number of red marbles = 3

Number of yellow marbles = 4

Number of green marbles = 6

Total number of marbles = 3 +4 +6 = 13

​a) the marble is​ red? ​

Probability of getting a red marble =
`(3)/(13)`

b) the marble is not​ yellow?

Probability of not getting yellow =
`(3+6)/(13)=(9)/(13)`

​c) the marble is either red or ​green?

Probability of getting either red or green = P(red) + P(green) =
`(3)/(13)+(6)/(13)=(9)/(13)`

d) the marble is neither red nor ​green?

Probability of getting neither red nor green = P(getting yellow) =
`(4)/(13)`

Hence, a)
`(3)/(13),\ b)(9)/(13)\ c)(9)/(13),\ d)(4)/(13)`