Answer:
The correct option is;
Jason's statement is correct. RST is the same orientation, shape, and size as ABC
Explanation:
Here we have
ABC = (2, 1), (3, 3), (4, 1)
RST = (-4, -2), (-3, 0), (-2, -2)
Therefore the length of the sides are as follows
AB =
![√((2-3)^2+(1-3)^2) = √(5)](https://img.qammunity.org/2021/formulas/mathematics/high-school/8x5uggnnos57b7xe6q5okvgq9yaxff99t3.png)
AC =
![√((2-4)^2+(1-1)^2) =2](https://img.qammunity.org/2021/formulas/mathematics/high-school/lbb3qygv6u0ka7nednpnd2h7n98q69zxmu.png)
BC =
![√((3-4)^2+(3-1)^2) = √(5)](https://img.qammunity.org/2021/formulas/mathematics/high-school/azx5uhv07pr125gn1x3zg5k6jhftsnbddc.png)
For triangle SRT we have
RS =
![√((-4-(-3))^2+(-2-0)^2) = √(5)](https://img.qammunity.org/2021/formulas/mathematics/high-school/3cexjh148z4uhc5z0v5q10p5fxcicse20k.png)
RT =
![√((-4-(-2))^2+(-2-(-2))^2) = 2](https://img.qammunity.org/2021/formulas/mathematics/high-school/4705xk3enl2cixqq2gtk0d8potoxyvkejs.png)
ST =
![√((-3-(-2))^2+(0-(-2))^2) = √(5)](https://img.qammunity.org/2021/formulas/mathematics/high-school/36e0hrkh28coga9dpm4ahhx1pldeb7ovx4.png)
Therefore their dimensions are equal
However the side with length 2 occurs between (2, 1) and (4, 1) in triangle ABC and between (-4, -2) and (-2, -2) in triangle RST
That is Jason's statement is correct. RST is the same orientation, shape, and size as ABC.