Question

you can use a torque feeler that consists of a meterstick held at the 0 cm end with a weight dangling from various positions along the stick. When the stick is held horizontally, torque produced when a 1 kg object hangs fromt he 50 cm mark. How much torque is exerted when the object is hung from the 75 cm mark

Answer 1

`T=7.3575\ N.m`

Step-by-step explanation:

Given:

length of the stick,
`l=100\ cm=1\ m`

position of holding the stick that acts as a hinge,
`f=0\ cm`

mass of the object,
`m=1\ kg`

position of hanging the mass on the meter stick,
`x=50\ cm=0.5\ m`

new position of hanging the mass,
`x'=75\ cm=0.75\ m`

Now the torque in the initial position:

`T=mg.x`

where:

`g=` acceleration due to gravity

`T=1* 9.81* 0.5`

`T=4.905\ N.m`

Now when the mass is at the new position:

`T=mg.x'`

`T=1* 9.81* 0.75`

`T=7.3575\ N.m`