Question

Line segment ba has endpoints b(-6,3) and a(-1,8). What are coordinates of the point located 1/5 of the way from B to A

Answer 1

`\vec C = (-5,4)`

Explanation:

The coordinates of the point located 1/5 of the way from B to A is:

`\vec C = \vec B + \alpha \cdot \overrightarrow {BA}`

`\vec C = (-6,3) + (1)/(5)\cdot (-1+6,8 - 3)`

`\vec C = (-6,3) + (1)/(5)\cdot (5,5)`

`\vec C = (-6,3) + (1,1)`

`\vec C = (-6+1,3+1)`

`\vec C = (-5,4)`