2 Answers

Breezymri · Answer 1 · 2021-08-07T10:42:34+0000

The figure on the top left is a triangle with base 11 and height 8, for an area of

$A_1=(11\cdot 8)/(2)=44$

Immediately below, we have a rectangle with dimensions 11 and 9, for an area of

$A_2=11\cdot 9=99$

Moving to the right, we have a parallelogram with base 9 and heght 11, which again has height

$A_3=11\cdot 9=99$

Finally, the rightmost figure is a triangle with base 8 and height 9, for a total of

$A_4=(8\cdot 9)/(4)=36$

Sum these areas and you'll get the total area

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