Answer: 48.11L
Step-by-step explanation:
The equation below shows how limited supply of air results in incomplete combustion of carbon which then leads to the formation of carbon monoxide gas
2C(s) + O2(g) ---> 2CO(g)
Given that:
Volume of CO (V) = ?
Temperature of CO gas (T) = 11°C
[Convert 11°C to Kelvin by adding 273
11°C + 273 = 284K]
Pressure of CO (P) = 600 mmHg
[convert 600 mmHg to atmosphere
If 760 mmHg = 1 atm
600 mmHg = 600/760 = 0.789 atm]
Number of moles of CO gas (n) = 1.63 moles
Molar gas constant (R) is a constant with a value of 0.082 atm L K-1 mol-1
Then, apply the formula for ideal gas equation
pV = nRT
0.789 atm x V = 1.63 moles x 0.082 atm L K-1 mol-1 x 284K
0.789 atm•V = 37.96 atm•L
Divide both sides by 0.789 atm to get V
0.789 atm•V/0.789 atm = 37.96 atm•L/0.789 atm
V = 48.11L
Thus, the volume of CO gas is 48.11 litres