Question

In ΔJKL, the measure of ∠L=90°, JL = 11, LK = 60, and KJ = 61. What is the value of the sine of ∠K to the nearest hundredth?

Answer 1

0.18

Explanation:

\sin K = \frac{\text{opposite}}{\text{hypotenuse}}=\frac{11}{61}\approx 0.1803\approx 0.18

sinK=

hypotenuse

opposite

​

=

61

11

​

≈0.1803≈0.18