Question

What function has zero at X equals 10 and X equals two

Answer 1

`\purple{ \boxed{ \bold{\therefore \: f(x) = {x}^(2) - 12x + 20 }}}`

Explanation:

`x = 10 \: \: and \: \: x = 2 \\ \therefore \: x - 10 = 0 \: \: and \: \: x - 2 = 0 \\let \: f(x) \: be \: the \: required \: function. \\\therefore \: f(x) = (x - 10)(x - 2) \\ \therefore \: f(x) = {x}^(2) + ( - 10 - 2)x + ( - 10)( - 2) \\ \red { \boxed{ \bold{\therefore \: f(x) = {x}^(2) - 12x + 20 }}}`

Hence, the function
`\orange { { \bold{\therefore \: f(x) = {x}^(2) - 12x + 20 }}}` has roots x = 10 and x = 2.