Answer: 2.22 litres
Step-by-step explanation:
Given that,
Original pressure of gas (P1) = 200.0 kPa
[Since final pressure is given in atmosphere, Convert 200.0 kPa to atmosphere
If 101.325 kPa = 1 atm
200.0 kPa = 200.0/101.325
= 1.9738 atm]
Original volume of oxygen O2 (V1) = 25.5L
New pressure of gas (P2) = 11.2 atm
New volume of gas (V2) = ?
Since pressure and volume are given while temperature is held constant, apply the formula for Boyle's law
P1V1 = P2V2
0.9738 atm x 25.5L = 11.2 atm x V2
24.8319 atm•L = 11.2 atm•V2
Divide both sides by 11.2 atm to get V2
24.8319 atm•L/11.2 atm = 11.2 atm•V2/11.2 atm
2.217 L = V2
[Round 2.217L to the nearest hundredth as 2.22L]
Thus, the new volume of the gas at 11.2 atm of pressure is 2.22 litres