Question

A bullet of mass 3.9 g was fired at a stationary ball of lead. The head-on impact moved the 10 kg ball at a velocity of 0.3703 m/s. If energy losses due to heat and internal energy are ignored, what was the speed of the bullet? (Round your answer to the nearest whole number.)

Answer 1

950 m/s

Step-by-step explanation:

The collision between the bullet and the lead ball is inelastic. To find the speed of the bullet use the equation;

3.9 x 10-3 + 10

3.9 x 10-3

x 0.3703

= 949.85

v1 = 950 m/s

Answer 2

Answer: 950m/s

Step-by-step explanation:

Got it right on USA test prep