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How many moles of gas are contained in a 30.0 L tube with a temperature of 300. K and pressure at 200. atm ?

244 Moles

1 Answer

1 vote

Answer:

Yes, 244 moles

Step-by-step explanation:

PV = nRT => n = PV/RT = (200atm)(30.0L)/(0.08206Latm/molK)(300K) = 243.7mol ≅ 244mol

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