Question

A proposed space elevator would consist of a cable stretching from the earth's surface to a satellite, orbiting far in space, that would keep the cable taut. A motorized climber could slowly carry rockets to the top, where they could be launched away from the earth using much less energy.

What would be the escape speed for a craft launched from a space elevator at a height of 56,000 km?

Answer 1

The escape speed for the craft is 1.49 m/s.

Step-by-step explanation:

In this case we need to find the escape speed for a craft launched from a space elevator at a height of 56,000 km. The escape velocity is given by :

`v=\sqrt{(2GM)/(d)}`

Here,

G is universal gravitational constant

M is mass of earth

d = r + h, r is radius of Earth

`v=\sqrt{(2* 6.67* 10^(-11)* 5.972 * 10^(24))/((6,371 * 10^3* 56000* 10^3))}\\\\v=1.49\ m/s`

So, the escape speed for the craft is 1.49 m/s.