Question

A 7.5 kg block is attached to a horizontally mounted spring with a spring constant of 750 J/m2 . The block is released from rest with the spring extended by 15 cm from its normal length. The block then oscillates back and forth along a horizontal and frictionless surface. How long will it take this system to complete one full oscillation?

Answer 1

It will take the system 0.63sec to complete one full oscillation

Step-by-step explanation:

The expression for period of a body in simple harmonic motion is

T=2*pi√m/k

Where T Is the period

m is the mass of the body

K is the spring constant

Given data

m = 7.5kg

e=15cm

k=750j/m2

Substituting our data into the expression

T=2*3.142 √ 7.5/750

T=6.284*0.1

T=0.63sec