Answer:
a)2.5
b) 1.37
c) -0.24, 5.24
d) 0.1460
e) 0.0420
Explanation:
Given:
n = 10
P = 1/4 = 0.25
a) expected number of answers
= n * p
= 10 * 0.25 = 2.5
b) standard deviation
![= √(np(1-p))](https://img.qammunity.org/2021/formulas/mathematics/high-school/674n3qdq2rfm7abvgr8cdxr7eecmp18vbf.png)
![= √(10*0.25*(1-0.25))](https://img.qammunity.org/2021/formulas/mathematics/high-school/b5gnxir7w0kbq79fs57lt54o3nnk4lqwyi.png)
= 1.37
c)• u-26 = 2.5 - 2(1.37)
= 2.5 - 2.75
= -0.24
• u+26= 2.5 + 2(1.37)
= 5.24
d) Pobability that the student answers exactly 4 questions correctly
![= P(x=4) = [10, 4] (0.25)^4 (0.75)^6](https://img.qammunity.org/2021/formulas/mathematics/high-school/jytv2qm76bro7xyvee0ncvjal5ecqolchi.png)
= 0.1460
e) P(x≥6)=P(x=6)+P(x=7)+P(x=8)+P(x=9)+P(x=10)
![= [10 ,6] (0.25)^6(0.75)^4+ [10, 7](0.25)^7(0.75)^3 + [10, 8](0.24)^8(0.75)^2 + [10, 9] (0.25)^9(0.75)^2 + [10, 10] (0.25)^10(0.75)^0](https://img.qammunity.org/2021/formulas/mathematics/high-school/bihazb68fij5de44wc2yaa9h2p35ehaaok.png)
= 0.03845+0.00309+0.00039+0.0000286+0.000000954
= 0.0420
(Part (e) is also attached for easier understanding)