Answer:
a) T = 1.405 s
b) Period not depends on the amplitude
c) T = 1.987 s
d) T = 0.811 s
e) The period will change by a small value
The rank are:
Tc > Ta = Tb > Te > Td
Step-by-step explanation:
Given:
m = mass = 0.3 kg
A = amplitude = 0.4 m
k = force constant = 6 N/m
a) The time period is:

b) Period not depends on the amplitude
c) Same as a):

d) Same as a):

e) if a small resistive force is added the period will change by a small amount. The rank are:
Tc > Ta = Tb > Te > Td