Question

Solve on the interval [0,2pi)
1+ sin 0=1/2​

Answer 1

sin(theta) = 7pi/6, 11pi/6

Explanation:

Start by replacing theta with x (they are the same thing in this case.

Next Solve...

1 + sin(x) = 1/2

sin(x) = -1/2 (subtract one from both sides)

Plug in y = sin(x) on a graphing calculator

Plug in y = -1/2

See where the points intersect between 0 and 2pi

They should intersect at 7pi/6 and 11pi/6