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A random sample of 64 SAT scores of students applying for merit scholarships showed an average of 1400 with a standard deviation of 240.

If we want to provide a 95% confidence interval for the SAT scores, the degrees of freedom for reading the critical values of "t" statistic is:_______.

User Bpedroso
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Answer:

Degree of freedom = 63

Explanation:

We are given the following in the question:

Sample size, n = 64

Sample mean = 1400

Sample standard deviation = 240

We need to make a 95% confidence interval.

We use the t-statistic for the same.

Degree of freedom:

  • It is the maximum number of logically independent values that have the freedom to vary, in the data sample.

Degree of freedom for reading the critical values of t-statistic is


= n =-1\\=64-1\\=63

Thus, the degree of freedom is 63.

User Dizzi
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