Answer:
da = 66 rev
The tub turn 66 revolutions while it is in motion
Question:
The tub of a washer goes into its spin cycle, starting from rest and gaining angular speed steadily for 9.00 s, at which time it is turning at 6.00 rev/s. At this point, the person doing the laundry opens the lid, and a safety switch turns off the washer. The tub smoothly slows to rest in 13.0 s. Through how many revolutions does the tub turn while it is in motion?
Step-by-step explanation:
Given:
Acceleration Time t1 = 9.00s
Deceleration Time t2 = 13.00s
Maximum angular velocity w2= 6.00rev/s
Initial and final angular speed w1= 0rev/s
Calculating the average angular velocity wa;
wa = (w1+w2)/2
wa = (6+0)/2
wa = 3 rev/s
Angular distance covered da= average angular velocity × time
da = wat1 + wat2
da = 3×9 + 3×13
da = 27+39
da = 66 rev
The tub turn 66 revolutions while it is in motion