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The tub of a washer goes into its spin cycle, starting from rest and gaining angular speed steadily for 9.00 s, at which time it is turning at 6.00 rev/s. At this point, the person doing the laundry opens the lid, and a safety switch turns off the washer. The tub smoothly slows to rest in 13.0 s. Through how many revolutions does the tub turn while it is in motion?

User Rob Kinyon
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2 Answers

3 votes

Answer:


n_(tot) = 66\,rev

Step-by-step explanation:

The total of revolutions during the whole process is:


n_(tot) = n_(1) + n_(2)

The acceleration of each stage is determined below:

Acceleration:


\ddot n_(1) = (\dot n_(1))/(t_(1))


\ddot n_(1) = (6\,(rev)/(s) )/(9\,s)


\ddot n_(1) = (2)/(3)\,(rev)/(s^(2))

Deceleration:


\ddot n_(2) = -(\dot n_(1))/(t_(2))


\ddot n_(2) = -(6\,(rev)/(s) )/(13\,s)


\ddot n_(2) = - (6)/(13)\,(rev)/(s^(2))

The total of revolutions during the process is:


n_(tot) = (1)/(2)\cdot \ddot n_(1)\cdot t_(1)^(2) + \dot n_(1)\cdot t_(2)+(1)/(2)\cdot \ddot n_(2)\cdot t_(2)^(2)


n_(tot) = (1)/(2)\cdot \left((2)/(3)\,(rev)/(s^(2)) \right)\cdot (9\,s)^(2) + \left(6\,(rev)/(s)\right)\cdot (13\,s) + (1)/(2)\cdot \left(-(6)/(13)\,(rev)/(s^(2)) \right) \cdot (13\,s)^(2)


n_(tot) = 66\,rev

User Rakesh Gourineni
by
4.2k points
5 votes

Answer:

da = 66 rev

The tub turn 66 revolutions while it is in motion

Question:

The tub of a washer goes into its spin cycle, starting from rest and gaining angular speed steadily for 9.00 s, at which time it is turning at 6.00 rev/s. At this point, the person doing the laundry opens the lid, and a safety switch turns off the washer. The tub smoothly slows to rest in 13.0 s. Through how many revolutions does the tub turn while it is in motion?

Step-by-step explanation:

Given:

Acceleration Time t1 = 9.00s

Deceleration Time t2 = 13.00s

Maximum angular velocity w2= 6.00rev/s

Initial and final angular speed w1= 0rev/s

Calculating the average angular velocity wa;

wa = (w1+w2)/2

wa = (6+0)/2

wa = 3 rev/s

Angular distance covered da= average angular velocity × time

da = wat1 + wat2

da = 3×9 + 3×13

da = 27+39

da = 66 rev

The tub turn 66 revolutions while it is in motion

User Npross
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4.4k points