H(1)=−2 h(2)=1 h(n)=h(n−2)+h(n−1) what is h(3)???

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asked Feb 12, 2021 146k views

1 vote

H(1)=−2
h(2)=1
h(n)=h(n−2)+h(n−1)
what is h(3)???

Mathematics
middle-school

Neutrinus asked

by Neutrinus

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2 Answers

5 votes

Answer:

-1

Explanation:

Mario Visic answered Feb 14, 2021

by Mario Visic

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4 votes

Answer:

h(3) = -1

Explanation:

h(n) = h(n-2) + h(n-1)

h(3) = -2 + 1

h (3) = -1

Mohammad Mazraeh answered Feb 16, 2021

by Mohammad Mazraeh

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