Question

Magnetic Field of a Current Loop: A wire carrying a current is shaped in the form of a circular loop of radius 4.0 mm. If the magnetic field strength at its center is 1.1 mT with no external magnetic fields present, what is the magnitude of the current flowing through the wire?

Answer 1

The magnitude of the current flowing through the wire is 7 A.

Step-by-step explanation:

Given that,

Radius of the circular loop, r = 4 mm = 0.004 m

Magnetic field at the centre of the loop, B = 1.1 mT

We need to find the magnitude of the current flowing through the wire. The magnetic field at the center of the loop is given by the formula as follows :

`B=(\mu_oI)/(2r)\\\\I=(2Br)/(\mu_o)\\\\I=(2* 1.1* 10^(-3)* 0.004)/(4\pi * 10^(-7))\\\\I=7\ A`

So, the magnitude of the current flowing through the wire is 7 A.