Answer:
Margin of error E = Z(alpha/2)*(sigma/sqrt(n))
From this equation we get n as
n = (z*sigma/E)^2
alpha= 0.02
from the standard normal table value we get
z(alpha/2) = 2.33
sigma = 30
E= 0.1
Therefore n =(2.33*30/0.1)^2
=488601
sample size n =488601