Question

The average flowrate of hydrochloric acid solution from a plant is 11,900 Lt/hr. The density is the same as that of water (1kg/Lt). The concentration of HCl in the solution is 0.015gmol/Lt.

Calculate the following:
(i) Flowrate in gallons per minute
(ii) Mass flowrate in lbm / hr
(iii) The number of gram mol of HCl flowing per minute
(iv) The mass fraction of HCl in the solution
(v) The number of lb mols of HCl in 1m3 of solution

Answer 1

See explanation.

Step-by-step explanation:

Hello,

Here, considering the given flowrate, we perform the following units conversions for each case:

(i)

`11,900 (L)/(h) *(0.264172 gal)/(1L) *(1h)/(60min) =52.39(gal)/(min)`

(ii)

`11,900 (L)/(h) *(1kg)/(1L)*(2.20462lbm)/(1kg)=26,234(lbm)/(h)`

(iii)

`11,900 (L)/(h) *(0.015gmolHCl)/(1L)*(1h)/(60min)=2.975(gmolHCl)/(min)`

(iv) We find the kg of HCl per kg of acid solution:

`w_(HCl)=0.015(gmolHCl)/(Lsln)*(36.45gHCl)/(1gmolHCl) *(1kgHCl)/(1000gHCl)*(1Lsln)/(1kgsln) =5.4675x10^(-4)`

(v)

`n_(HCl)=0.015(gmolHCl)/(L)*(1000L)/(1m^3) *1m^3=15gmolHCl`

Best regards.