Question

Using a 681 nm 681 nm wavelength laser, you form the diffraction pattern of a 1.1 mm 1.1 mm wide slit on a screen. You measure on the screen that the 12 th 12th dark fringe is 8.63 cm 8.63 cm away from the center of the central maximum. How far is the screen located from the slit?

Answer 1

The distance of the screen from the slit is
`D= 11.62m`

Step-by-step explanation:

From the question we are told that

The wavelength of the laser is
`\lambda = 681nm = (681)/(1*10^(-9)) = 681 *10^(-9)m`

The width of the slit is
`w_s = 1.1mm = (1.1)/(1000) =1.1 *10^(-3)m`

The number of dark fringe that is being considered
`n =12`

The distance to the center of the central maximum is
`d = 8.63\ cm = (8.63)/(100) = 8.63 * 10^ {-2}m`

The distance of the screen from the is mathematically represented as

`D = (d * w_s)/(n* \lambda)`

Substituting values we have

`D = (8.63*10^(-2) * 1.1*10^(-3))/(12 * 681 *10^(-9))`

`D= 11.62m`