Question

Three men and seven women are waiting to be interviewed for jobs. If they are all selected in random​ order, find the probability that no man will be interviewed until at least two women have been interviewed. The probability is nothing.

Answer 1

1/50

Explanation:

Given that:

• Three men: 3
• Seven women = 7
• Total number of people: 7+3 =10

We need to find the probability that no man will be interviewed until at least two women have been interviewed. So there are two possible probabilities are:

1. One man and two women => P(1 man and 2 women) = 3/10*2/9 = 1/15

2. Three women => P(3 women) = 3/10

Hence, the probability in this situation is: 1/15*3/10 = 1/50