The slope of JK is -6/5.
The slope of PQ is 12/ 15.
These lines are neither parallel nor perpendicular.
Explanation:
From the graph shown,
It can be determined that the point J is (0,5) and K is (10,-7).
The point P is (-5,-8) and Q is (10,4).
The formula for slope is given by,
Slope =
![(y2-y1)/(x2-x1)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/flm5n96lsu1pl0daqmknr0jcmu4wjdbkcc.png)
To find the slope of line JK :
J ⇒ (0,5) = (x1,y1)
K ⇒ (10,-7) = (x2,y2)
Slope of JK =
![(-7-5)/(10-0)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/5vhhvgctfcqjqdv5fapl7ydm7qrl55iy3e.png)
⇒
![(-12)/(10)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/3nounr1etcyxk4gzsmqzh0ybceqnahv9hi.png)
⇒
![(-6)/(5)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/gnzthvz1swz9tm5j339s3lvsealdgfh0um.png)
∴ The slope of JK is -6/5.
To find the slope of line PQ :
P ⇒ (-5,-8) = (x1,y1)
Q ⇒ (10,4) = (x2,y2)
Slope of PQ =
![(4+8)/(10+5)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/oethnnhocwrz4ocr2r6hyvxjrymi4ntzx7.png)
⇒
![(12)/(15)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/89l9tbopotc8hq4v0p379jz3s06l7x7s8y.png)
∴ The slope of PQ is 12/ 15.
To find the relation between two lines :
- The parallel lines have same slope.
- The perpendicular lines have a slope of negative reciprocal.
∴ These lines are neither parallel nor perpendicular.