Question

Suppose a pendulum bob is swinging back and forth. If the highest point is 12.5 cm above the lowest point, what would be speed of the bob in m/s when it passes the lowest point (no friction or air resistance)? Think Conservation of Mechanical Energy.

Answer 1

The speed of the bob when it passes the lowest point
`V = 1.57 (m)/(s)`

Step-by-step explanation:

Given data

`H = 12.5 \ cm = 0.125 \ m\\`

When a pendulum swinging back & forth then at highest point the velocity is zero and lowest point velocity is maximum.

Velocity at lowest point is given by

`V = √(2 g H)`

`V = √(2 (9.81)(0.125))`

`V = 1.57 (m)/(s)`

Therefore the speed of the bob when it passes the lowest point
`V = 1.57 (m)/(s)`