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Suppose a pendulum bob is swinging back and forth. If the highest point is 12.5 cm above the lowest point, what would be speed of the bob in m/s when it passes the lowest point (no friction or air resistance)? Think Conservation of Mechanical Energy.

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Answer:

The speed of the bob when it passes the lowest point
V = 1.57 (m)/(s)

Step-by-step explanation:

Given data


H = 12.5 \ cm = 0.125 \ m\\

When a pendulum swinging back & forth then at highest point the velocity is zero and lowest point velocity is maximum.

Velocity at lowest point is given by


V = √(2 g H)


V = √(2 (9.81)(0.125))


V = 1.57 (m)/(s)

Therefore the speed of the bob when it passes the lowest point
V = 1.57 (m)/(s)

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