Question

Assume a satellite shines an unpolarized light on a telescope. The intensity of the light as it reaches the telescope is 1.1*10-10 W/m2 a lit, 1000-watt light bulb mounted on it. The unpolarized light from the light bulb, upon reaching the telescope, is passed through two polarizing filters that are at an angle of 30° with respect to each other, and then the resulting light is projected onto a CCD camera. What is the intensity of the light detected by the camera?

Answer 1

`4.125* 10^(-11)\ W/m^2`

Step-by-step explanation:

`I_0` = Intensity of unpolarized light =
`1.1* 10^(-10)\ W/m^2`

`\theta` = Angle of the filter =
`30^(\circ)`

Intensity of light is given by

`I=(I_0)/(2)cos^2\theta\\\Rightarrow I=(1.1* 10^(-10))/(2)cos^230\\\Rightarrow I=4.125* 10^(-11)\ W/m^2`

The intensity of light detected by the camera is
`4.125* 10^(-11)\ W/m^2`