Answer:
Electric field is 2.67 x 10⁻⁶ N/C
Step-by-step explanation:
Charge of Sodium ion, q = 6 x 10^8 x 1.6 x 10^-19 = 9.6 x 10^-11 C
Since;
Electric field, E = 2 kdq / Kr^3
Substituting all given parameters
E = (2 x 9 x 10⁹ x 8 x 10⁻⁹ x 9.6 x 10⁻¹¹) / (81 x 0.04³)
E = 2.67 x 10⁻⁶ N/C