Question

Let's begin by calculating the mass of the puck, which will be needed at various points throughout this tutorial. Using the density of dry ice (1.50 g/cm3) and the dimensions of the puck, find the mass of the puck. Assume the height of the puck is 2.60 cm.

Answer 1

`12.25 r^2` kg where r (cm) is the radius of the puck

Step-by-step explanation:

Assuming the radius of the puck is r (cm), we can first calculate the volume v of the puck as the product of its base area a and the height h

`v = ah = \pi r^2 h` cubic centimetres

Then the mass m of the puck would be product of the volume and the puck density ρ

`m = v\rho = \pi r^2 h \rho = 1.5*2.6 \pi r^2 = 12.25 r^2`kg