Question

Dalton's Law of Partial pressure: The total pressure of a gas mixture is the sum of the partial pressures of each gas . Therefore if I have a gas chamber with 3.1 atm of Xe and 0.8 atm of N2 and no H2,.. What is the pressure in the chamber.

Answer 1

The total pressure of this gas mixture in the chamber is 3.9 atm

Step-by-step explanation:

Step 1: Data given

Partial pressure of Xe = 3.1 atm

Partial pressure of N2 = 0.8 atm

Partial pressure of H2= 0 atm

Dalton's law says: Total pressure of a gas mixture = sum of partial pressure of gasses

Step 2: Calculate the total pressure of a gas mixture

Dalton's law says: Total pressure of a gas mixture = sum of partial pressure of gasses

Total pressure of the gas mixture = Partial pressure of Xe + Partial pressure of N2 + partial pressure of H2

Total pressure of the gas mixture = 3.1 atm + 0.8 atm + 0 atm

Total pressure of the gas mixture = 3.9 atm

The total pressure of this gas mixture in the chamber is 3.9 atm

Answer 2

Total Pressure = 3.9atm

Step-by-step explanation:

Dalton's law says the pressure of a gas mixture is the sum of partial pressures of each gas.

In the problem, you have two gases in a chamber: Xe, N₂.

Thus, pressure of chamber is:

Total Pressure = Pressure Xe + Pressure N₂

Total Pressure = 3.1 atm + 0.8 atm

Total Pressure = 3.9atm