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How many different orders can be formed for a 9 member baseball team

User Wurde
by
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1 Answer

3 votes

Answer:

362,880

Explanation:

If there are 9 players for the 1st position, 8 for the 2nd and so on so on, you can multiply all the numbers 1-9 together (i.e 9×8×7×6×5×4×3×2×1= 362,880)

**This is if it's asking for how many different batting orders are possible**

User Serious
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