Answer:
1)
![m_(O_2)=24.5gO_2](https://img.qammunity.org/2021/formulas/chemistry/college/nyi29vsa032cl2jajkxc3iwaofkbgx01i5.png)
2)
![m_(CO_2)=33.7gCO_2](https://img.qammunity.org/2021/formulas/chemistry/college/paa31fw3ew5b582i64gir1yqwf5xslviki.png)
Step-by-step explanation:
Hello,
1) In this case, by considering the given reaction, starting by 23.0 g of glucose, the grams of oxygen by stoichiometry result:
![m_(O_2)=23.0gC_6H_(12)O_6*(1molC_6H_(12)O_6)/(180gC_6H_(12)O_6)*(6molO_2)/(1molC_6H_(12)O_6)*(32gO_2)/(1molO_2) \\m_(O_2)=24.5gO_2](https://img.qammunity.org/2021/formulas/chemistry/college/krtpzzuu4powwpxza6ixc2nxjdg6116vk9.png)
2), Now, by means of also stoichiometry, the grams of carbon dioxide that are produced result:
![m_(CO_2)=23.0gC_6H_(12)O_6*(1molC_6H_(12)O_6)/(180gC_6H_(12)O_6)*(6molCO_2)/(1molC_6H_(12)O_6)*(44gCO_2)/(1molCO_2)\\m_(CO_2)=33.7gCO_2](https://img.qammunity.org/2021/formulas/chemistry/college/yra02ex8ip7hhlthvf71b5lq0jcw6uqvm9.png)
Best regards.