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Glucose, C6H12O6, is used as an energy source by the human body. The overall reaction in the body is described by the equation:

C6H12O6(aq) + 6O2(g) ⟶ 6CO2(g) + 6H2O(l)
1) Calculate the number of grams of oxygen required to convert 23.0 g of glucose to CO2 and H2O.
2) Calculate the number of grams of CO2 produced.

1 Answer

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Answer:

1)
m_(O_2)=24.5gO_2

2)
m_(CO_2)=33.7gCO_2

Step-by-step explanation:

Hello,

1) In this case, by considering the given reaction, starting by 23.0 g of glucose, the grams of oxygen by stoichiometry result:


m_(O_2)=23.0gC_6H_(12)O_6*(1molC_6H_(12)O_6)/(180gC_6H_(12)O_6)*(6molO_2)/(1molC_6H_(12)O_6)*(32gO_2)/(1molO_2) \\m_(O_2)=24.5gO_2

2), Now, by means of also stoichiometry, the grams of carbon dioxide that are produced result:


m_(CO_2)=23.0gC_6H_(12)O_6*(1molC_6H_(12)O_6)/(180gC_6H_(12)O_6)*(6molCO_2)/(1molC_6H_(12)O_6)*(44gCO_2)/(1molCO_2)\\m_(CO_2)=33.7gCO_2

Best regards.

User Laura Maftei
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