Answer:
Value of factor 2πf in radians per second for this frequency is 377 rad/s.
Step-by-step explanation:
Given :
Equation of output voltage ,
![V=V_o\ sin( 2\pi ft)](https://img.qammunity.org/2021/formulas/physics/college/gqmhkoc861xi9aw6ikbi4kg5e8cscoht3v.png)
Frequency , f = 60 Hz .
We know , frequency is converted to angular frequency with units rad /s as :
![\omega=2\pi f](https://img.qammunity.org/2021/formulas/physics/college/nxfe0x4xiijz5ywyagqb92iq1fg483g74t.png)
Putting value of f in above equation .
We get :
![\omega=2* \pi * 60\\\omega = 376.99\ rad/s\\or\ , \omega=377 \ rad/s](https://img.qammunity.org/2021/formulas/physics/college/e5frhx5j97kyhx8sqikn9lvatl20b0oobw.png)
So , value of factor 2πf in radians per second for this frequency is 377 rad/s.