Question

For your selection above, substitute ???? = 2???????? T where T is the period of orbit. Kepler found that the cube of orbital radius was proportional to the square of orbital period. Do your findings confirm or contradict Kepler’s Rule?

Answer 1

So, the findings will confirm Kepler's rule if for any two set of planets, if T₁²/R₁³= T₂²/R₃³ and contradict if T₁²/R₁³≠ T₂²/R₃³

Step-by-step explanation:

Kepler has three laws of planetary orbit

1. The planets move around the sun in elliptical orbits with the sun at the center of the orbit.

2. The line joining the sun and the planet sweeps out equal areas in equal times.

3. The square of the period of revolution of the planet about the sun is directly proportional to the cube of its average distance from the sun.

We are going to consider the third law here

Let T be the orbital period about the sun and R be its orbital radius. From Kepler's third law, it follows that T² ∝ R³ and T²/R³ = constant for any planet.

So, the findings will confirm Kepler's rule if for any two set of planets, if T₁²/R₁³= T₂²/R₃³ and contradict if T₁²/R₁³≠ T₂²/R₃³