Air is to be compressed so that its volume is reduced to half of its original volume if the initial pressure is 200 kPa and the temperature is 20°C. Assume the ratio of specific…

Question

asked Mar 4, 2021 126k views

1 Answer

Eino Gourdin · Answer 1 · 2021-03-10T02:21:53+0000

Answer:

$P_(2) = 527.803\,kPa$

Step-by-step explanation:

The politropic relationship for a isentropic process is:

$(P_(2))/(P_(1)) = \left((V_(1))/(V_(2)) \right)^(\gamma)$

Where
$\gamma$ is the ratio of specific heats

The final pressure is:

$P_(2) = P_(1)\cdot \left((V_(1))/(V_(2))\right)^(\gamma)$

$P_(2) = (200\,kPa)\cdot (2)^(1.4)$

$P_(2) = 527.803\,kPa$