Question

Problem situation:

Anna is at the movie theater and has $35 to spend.
She spends $9.50 on a ticket and wants to buy some snacks. Each snack costs $3.50.
How many snacks, x, can Anna buy?

Inequality that represents this situation:
9.50+3.50x≤35

Drag each number to show if it is a solution to both the inequality and the problem situation, to the inequality only, or if it is not a solution.

Solution to both the inequality and the situation

Solution to the inequality only

Not a solution

Answer 1

Explanation:

Amount of money Anna has = $ 35

Money she spent on the ticket = $9.50

Money she spent on snacks = $ 3.50

Let x number of snacks, which will be the least number of snacks that Anna can buy.

transforming the situation in terms of inequality

→9.50 +3.50 x≤ 35

→9.50 -9.50+3.50 x≤35-9.50

→3.50 x≤25.50

Dividing both sides by 3.50, we get

→x≤7.3(approx)

which can't be the number of snacks, as it will be an integral value.

So, the minimum number of snacks with the given amount of money = 7

So, Anna can buy snacks(x)={x:x≤7,x=1,2,3,4,5,6,7}=At most 7.