Answer:
1.09 m/s²
Step-by-step explanation:
Given:
Final speed of the sprinter (v) = 10.4 m/s
Initial speed of the sprinter (u) = 0 m/s (As the sprinter starts from rest position)
Time taken to reach the speed(Δt) = 9.58 s
Average acceleration is defined as the rate of change of velocity.
So, the acceleration of the sprinter is given as:

Plug in all the given values and solve for acceleration, 'a'. This gives,

Therefore, the magnitude of the average acceleration of the sprinter is 1.09 m/s².