Question

a certain experiment, a radio transmitter emits sinusoidal electromagnetic waves of frequency 110.0 MHz in opposite directions inside a narrow cavity with reflectors at both ends, causing a standing-wave pattern to occur. (a) How far apart are the nodal planes of the magnetic field

Answer 1

1.364 m

Step-by-step explanation:

We are given that

Frequency,f=110 MHz=
`110* 10^(6)Hz`

`1MHz=10^6Hz`

We have to find the distance between the nodal planes of the magnetic field.

We know that

Wavelength,
`\lambda=(c)/(f)`

Where c=
`3* 10^8m/s`

Using the formula

`\lambda=(3* 10^8)/(110* 10^6)=2.727 m`

Distance between nodal planes of the magnetic field

`d=(\lambda)/(2)`

`d=(2.727)/(2)=1.364 m`