Question

Falling objects drop with an average acceleration of 9.8 m/s2. An arrow is shot with a velocity of 11.76 m/s straight down from the top of a tall castle hitting an armored knight with a downward velocity of 49 m/s. How long was the arrow in flight?

Answer 1

3.8 secs

Step-by-step explanation:

Parameters given:

Acceleration due to gravity, g = 9.8
`m/s^2`

Initial velocity, u = 11.76 m/s

Final velocity, v = 49 m/s

Using one of Newton's equations of linear motion, we have that:

`v = u + gt`

where t = time of flight of arrow

The sign is positive because the arrow is moving downward, in the same direction as gravitational force.

Therefore:

`49 = 11.76 + 9.8*t\\\\\\\49 - 11.76 = 9.8t\\\\=> 9.8t = 37.24\\\\\\t = (37.24)/(9.8) \\\\\\t = 3.8 secs`

The arrow was in flight for 3.8 secs