Answer:
power = 5.7 kW
Step-by-step explanation:
given data
plant flow Q = 3,780 m³/day
velocity gradient =
/s
viscosity (m) is 0.001307 N-s/m²
solution
we get here first volume of mining vessel that is express as
volume = Q × ∅
volume = 3,780 × 1 sec ×
×
volume = 0.044 m³
and
now we get here power that is
power = velocity gradient² × viscosity × volume ......................1
power = 0.001307 × (
)² × 0.044
power = 5.7 kW